WebOct 27, 2024 · 1 Answer Sorted by: 31 You need to declare that weight is global inside GetLiveWeight, not outside it. weight = 'value' def GetLiveWeight (): global weight The global statement tells Python that within the scope of the GetLiveWeight function, weight refers to the global variable weight, not some new local variable weight. Share Improve … WebFeb 24, 2024 · As shown above, the .update() method accepts as an argument not only another dictionary, but also a list of tuples or keyword arguments.This method modifies …

Python Dictionary update() Method - W3School

WebAug 11, 2014 · RuntimeError: dictionary changed size during iteration If you instead use d.items (), then it works. In Python 3, d.items () is a view into the dictionary, like d.iteritems () in Python 2. To do this in Python 3, instead use d.copy ().items (). WebMay 15, 2012 · Add a comment. 3. You can do this: # list index l_index=0 # iterate over all dictionary objects in dict1 list for d in dict1: # add a field "count" to each dictionary object with # the appropriate value from the list d ["count"]=list1 [l_index] # increase list index by one l_index+=1. This solution doesn't create a new list. little bear riaa

Incrementing a numerical value in a dictionary - Stack Overflow

WebJun 10, 2014 · There are a few ways to make it change: You can directly update it: menu_data ['lightHourConfig'] = 20 But you would have to do that for every place that it appears. Another way would be to initialize lightHourConfig as a dict: lightHourConfig = {"value" : 24} Then somewhere else when you change the value like so: lightHourConfig … WebMar 20, 2024 · I have a dictionary contains 5 years, for year 2015, dictionary looks like below image, with row,col = 6781: 2015 i want to update the values based on another array [22 22 22 ... 2 22 1] size of 6781 I do this line of code: feat_landcov [str (year)] [col, row] = values however, i keep getting index out of bounds error. little bear rat attack review